y=0.6y+0.1y^2

Solution for y=0.6y+0.1y^2 equation:

y=0.6y+0.1y^2

We move all terms to the left:

y-(0.6y+0.1y^2)=0

We get rid of parentheses

-0.1y^2-0.6y+y=0

We add all the numbers together, and all the variables

-0.1y^2+0.4y=0

a = -0.1; b = 0.4; c = 0;
Δ = b2-4ac
Δ = 0.42-4·(-0.1)·0
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{0.16}}{2*-0.1}=\frac{-0.4-\sqrt{0.16}}{-0.2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{0.16}}{2*-0.1}=\frac{-0.4+\sqrt{0.16}}{-0.2}
$